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- Equation (3.54) can be thought of as an
equation in an
dimensional vector space
with a linear operator
F acting on a vector function
a(t) on the
right hand side, and a differential operator acting
on
a(t) on the left hand side.
There is a standard way to solve such equations. The
way is as follows:
- If
F is a normal
operator,
i.e.,
then
it is possible to find such rotation
in
,
i.e., such transformation
that
when we rotate the basis of the vector space,
the operator
F in the new basis
will be diagonal.
- If
F is not normal
then a diagonalizing transformation
still exists, but it may not be in
.
This is not a big problem: things just get a little
more messy.
- Once
F has been diagonalized
equation (3.54) splits into
n independent differential equations
that can be solved trivially.
- Then we have to rotate things back to the original
basis.
Zdzislaw Meglicki
2001-02-26